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本文小編為大家詳細介紹“Python中如何移除List重復項”,內容詳細,步驟清晰,細節處理妥當,希望這篇“Python中如何移除List重復項”文章能幫助大家解決疑惑,下面跟著小編的思路慢慢深入,一起來學習新知識吧。
這種方式是在遍歷整個list的基礎上,將第一個出現的元素添加在新的列表中。
示例代碼:
# Python 3 code to demonstrate
# removing duplicated from list
# using naive methods
# initializing list
test_list = [1, 3, 5, 6, 3, 5, 6, 1]
print ("The original list is : " + str(test_list))
# using naive method
# to remove duplicated
# from list
res = []
for i in test_list:
if i not in res:
res.append(i)
# printing list after removal
print ("The list after removing duplicates : " + str(res))
→ 輸出結果:
The original list is : [1, 3, 5, 6, 3, 5, 6, 1]
The list after removing duplicates : [1, 3, 5, 6]
這種方式實際上是第一種方法的簡化版,它利用列表解析式,使用一行代碼就可以替代上面的循環方式。
示例代碼:
# Python 3 code to demonstrate
# removing duplicated from list
# using list comprehension
# initializing list
test_list = [1, 3, 5, 6, 3, 5, 6, 1]
print ("The original list is : " + str(test_list))
# using list comprehension
# to remove duplicated
# from list
res = []
[res.append(x) for x in test_list if x not in res]
# printing list after removal
print ("The list after removing duplicates : " + str(res))
→ 輸出結果:
The original list is : [1, 3, 5, 6, 3, 5, 6, 1]
The list after removing duplicates : [1, 3, 5, 6]
這種方式是最流行的方法來去除列表中的重復元素。但該方法的最大的一個缺點就是使用過后列表中元素的順序不再繼續保持與原來一致了。
示例代碼:
# Python 3 code to demonstrate
# removing duplicated from list
# using set()
# initializing list
test_list = [1, 5, 3, 6, 3, 5, 6, 1]
print ("The original list is : " + str(test_list))
# using set()
# to remove duplicated
# from list
test_list = list(set(test_list))
# printing list after removal
# distorted ordering
print ("The list after removing duplicates : " + str(test_list))
→ 輸出結果:
The original list is : [1, 5, 3, 6, 3, 5, 6, 1]
The list after removing duplicates : [1, 3, 5, 6]
該方法是在列表解析式的基礎上利用枚舉來去除重復元素。通過檢查元素是否已經在列表中存在從而將其略過。這種方法可以保持列表中的元素順序不會改變。
示例代碼:
# Python 3 code to demonstrate
# removing duplicated from list
# using list comprehension + enumerate()
# initializing list
test_list = [1, 5, 3, 6, 3, 5, 6, 1]
print ("The original list is : " + str(test_list))
# using list comprehension + enumerate()
# to remove duplicated
# from list
res = [i for n, i in enumerate(test_list) if i not in test_list[:n]]
# printing list after removal
print ("The list after removing duplicates : " + str(res))
→ 輸出結果:
The original list is : [1, 5, 3, 6, 3, 5, 6, 1]
The list after removing duplicates : [1, 5, 3, 6]
這是完成特殊任務中最快的方法。它先是將列表中的重復項移除并返回一個字典,最后轉換成列表。這種方法對于字符串也可以進行處理。
示例代碼:
# Python 3 code to demonstrate
# removing duplicated from list
# using collections.OrderedDict.fromkeys()
from collections import OrderedDict
# initializing list
test_list = [1, 5, 3, 6, 3, 5, 6, 1]
print ("The original list is : " + str(test_list))
# using collections.OrderedDict.fromkeys()
# to remove duplicated
# from list
res = list(OrderedDict.fromkeys(test_list))
# printing list after removal
print ("The list after removing duplicates : " + str(res))
→ 輸出結果:
The original list is : [1, 5, 3, 6, 3, 5, 6, 1]
The list after removing duplicates : [1, 5, 3, 6]
對于多維列表(列表嵌套)中的重復元素去除。這里假設列表中元素(也是列表)它們具有相同的元素(但不一定順序相同)都被當做重復元素。那么下面使用 set() + sorted() 方法來完成任務。
示例代碼:
# Python3 code to demonstrate
# removing duplicate sublist
# using set() + sorted()
# initializing list
test_list = [[1, 0, -1], [-1, 0, 1], [-1, 0, 1],
[1, 2, 3], [3, 4, 1]]
# printing original list
print("The original list : " + str(test_list))
# using set() + sorted()
# removing duplicate sublist
res = list(set(tuple(sorted(sub)) for sub in test_list))
# print result
print("The list after duplicate removal : " + str(res))
→ 輸出結果:
The original list : [[1, 0, -1], [-1, 0, 1], [-1, 0, 1], [1, 2, 3], [3, 4, 1]]
The list after duplicate removal : [(-1, 0, 1), (1, 3, 4), (1, 2, 3)]
也可以利用 set() + map() + sorted()
示例代碼:
# Python3 code to demonstrate
# removing duplicate sublist
# using set() + map() + sorted()
# initializing list
test_list = [[1, 0, -1], [-1, 0, 1], [-1, 0, 1],
[1, 2, 3], [3, 4, 1]]
# printing original list
print("The original list : " + str(test_list))
# using set() + map() + sorted()
# removing duplicate sublist
res = list(set(map(lambda i: tuple(sorted(i)), test_list)))
# print result
print("The list after duplicate removal : " + str(res))
→ 輸出結果:
The original list : [[1, 0, -1], [-1, 0, 1], [-1, 0, 1], [1, 2, 3], [3, 4, 1]]
The list after duplicate removal : [(-1, 0, 1), (1, 3, 4), (1, 2, 3)]
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