C#怎么通過HttpWebRequest發送帶有JSON Body的POST請求

本篇內容介紹了“C#怎么通過HttpWebRequest發送帶有JSON Body的POST請求”的有關知識，在實際案例的操作過程中，不少人都會遇到這樣的困境，接下來就讓小編帶領大家學習一下如何處理這些情況吧！希望大家仔細閱讀，能夠學有所成！

目錄

• 原來的處理方式
  

• 新的方式
  

原來的處理方式

通過 GetRequestStream 來獲取請求流，后把需要發送的 Json 數據寫入到流中

private T PostDataViaHttpWebRequest<T>(string baseUrl,
            IReadOnlyDictionary<string, string> headers,
            IReadOnlyDictionary<string, string> urlParas,
            string requestBody=null)
        {
            var resuleJson = string.Empty;
            try
            {
                var apiUrl = baseUrl;

                if (urlParas != null)
                    urlParas.ForEach(p =>
                    {
                        if (apiUrl.IndexOf("{" + p.Key + "}") > -1)
                        {
                            apiUrl = apiUrl.Replace("{" + p.Key + "}", p.Value);
                        }
                        else
                        {
                            apiUrl += string.Format("{0}{1}={2}", apiUrl.Contains("?") ? "&" : "?", p.Key, p.Value);
                        }
                    }
                );
                
                var req = (HttpWebRequest)WebRequest.Create(apiUrl);
                req.Method = "POST";
                req.ContentType = "application/json"; 
                req.ContentLength = 0;

                if (!requestBody.IsNullOrEmpty())
                {
                    using (var postStream = req.GetRequestStream())
                    {
                        var postData = Encoding.ASCII.GetBytes(requestBody);
                        req.ContentLength = postData.Length;
                        postStream.Write(postData, 0, postData.Length);
                    }
                }

                if (headers != null)
                {
                    if (headers.Keys.Any(p => p.ToLower() == "content-type"))
                        req.ContentType = headers.SingleOrDefault(p => p.Key.ToLower() == "content-type").Value;
                    if (headers.Keys.Any(p => p.ToLower() == "accept"))
                        req.Accept = headers.SingleOrDefault(p => p.Key.ToLower() == "accept").Value;
                }

                var response = (HttpWebResponse)req.GetResponse();

                using(Stream stream = response.GetResponseStream())
                {
                    using (StreamReader reader = new StreamReader(stream, Encoding.GetEncoding("UTF-8")))
                    {
                        resuleJson = reader.ReadToEnd();
                    }
                }
            }
            catch (Exception ex)
            {
                return default(T);
            }
            return JsonConvert.DeserializeObject<T>(resuleJson);
        }

但是會發現，數據一直沒有正常發送過去，而且代碼還顯得比較復雜

新的方式

這里修改一下寫入 RequestStream 的方式，使用 StreamWriter 包裝一下，然后直接寫入需要發送的 Json 數據

private T PostDataViaHttpWebRequest<T>(string baseUrl,
            IReadOnlyDictionary<string, string> headers,
            IReadOnlyDictionary<string, string> urlParas,
            string requestBody=null)
        {
            var resuleJson = string.Empty;
            try
            {
                var apiUrl = baseUrl;

                if (urlParas != null)
                    urlParas.ForEach(p =>
                    {
                        if (apiUrl.IndexOf("{" + p.Key + "}") > -1)
                        {
                            apiUrl = apiUrl.Replace("{" + p.Key + "}", p.Value);
                        }
                        else
                        {
                            apiUrl += string.Format("{0}{1}={2}", apiUrl.Contains("?") ? "&" : "?", p.Key, p.Value);
                        }
                    }
                );
                
                var req = (HttpWebRequest)WebRequest.Create(apiUrl);
                req.Method = "POST";
                req.ContentType = "application/json"; //Defalt

                if (!requestBody.IsNullOrEmpty())
                {
                    using (var postStream = new StreamWriter(req.GetRequestStream()))
                    {
                        postStream.Write(requestBody);
                    }
                }

                if (headers != null)
                {
                    if (headers.Keys.Any(p => p.ToLower() == "content-type"))
                        req.ContentType = headers.SingleOrDefault(p => p.Key.ToLower() == "content-type").Value;
                    if (headers.Keys.Any(p => p.ToLower() == "accept"))
                        req.Accept = headers.SingleOrDefault(p => p.Key.ToLower() == "accept").Value;
                }

                var response = (HttpWebResponse)req.GetResponse();

                using(Stream stream = response.GetResponseStream())
                {
                    using (StreamReader reader = new StreamReader(stream, Encoding.GetEncoding("UTF-8")))
                    {
                        resuleJson = reader.ReadToEnd();
                    }
                }
            }
            catch (Exception ex)
            {
                return default(T);
            }
            return JsonConvert.DeserializeObject<T>(resuleJson);
        }

這樣即可正確發送 Json 數據。

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