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怎么在golang中通過遞歸遍歷生成樹狀結構?相信很多沒有經驗的人對此束手無策,為此本文總結了問題出現的原因和解決方法,通過這篇文章希望你能解決這個問題。
golang 是Google開發的一種靜態強類型、編譯型、并發型,并具有垃圾回收功能的編程語言,其語法與 C語言相近,但并不包括如枚舉、異常處理、繼承、泛型、斷言、虛函數等功能。
通過遞歸和指針,嵌套成對應的結構體;
借鑒了前人的代碼,但是最后遞歸的指針調用自己也是調試了半天才出來,這里獻上完整的示例代碼.
package main import ( "fmt" "encoding/json" ) type dept struct { DeptId string `json:"deptId"` FrameDeptStr string `json:"frameDeptStr"` Child []*dept `json:"child"` } func main() { depts := make([]dept,0) var a dept a.DeptId = "1" a.FrameDeptStr = "" depts = append(depts,a) a.DeptId="3" a.FrameDeptStr = "1" depts = append(depts,a) a.DeptId="4" a.FrameDeptStr = "1" depts = append(depts,a) a.DeptId="5" a.FrameDeptStr = "13" depts = append(depts,a) a.DeptId="6" a.FrameDeptStr = "13" depts = append(depts,a) fmt.Println(depts) deptRoots := make([]dept,0) for _,v := range depts{ if v.FrameDeptStr == ""{ deptRoots= append(deptRoots,v) } } pdepts := make([]*dept,0) for i,_ := range depts{ var a *dept a = &depts[i] pdepts = append(pdepts,a) } //獲取了根上的科室 fmt.Println("根上的科室有:",deptRoots) var node *dept node = &depts[0] makeTree(pdepts,node) fmt.Println("the result we got is",pdepts) data, _ := json.Marshal(node) fmt.Printf("%s", data) } func has(v1 dept,vs []*dept) bool { var has bool has = false for _,v2 := range vs { v3 := *v2 if v1.FrameDeptStr+v1.DeptId == v3.FrameDeptStr{ has = true break } } return has } func makeTree(vs []*dept,node *dept) { fmt.Println("the node value in maketree is:",*node) childs := findChild(node,vs) fmt.Println(" the child we got is :",childs) for _,child := range childs{ fmt.Println("in the childs's for loop, the child's address here is:",&child) node.Child = append(node.Child,child) fmt.Println("in the child's for loop, after append the child is:",child) if has(*child,vs) { fmt.Println("i am in if has") fmt.Println("the child in if has is:",*child) fmt.Println("the child in if has 's address is:",child) makeTree(vs,child) } } } func findChild(v *dept,vs []*dept)(ret []*dept) { for _,v2 := range vs{ if v.FrameDeptStr+v.DeptId == v2.FrameDeptStr{ ret= append(ret,v2) } } return }
通過frame_dept_str來確定科室之間的關系的, (a.frame_dept_str= a's parent's frame_dept_str + a's parent's dept_id).
補充:golang的樹結構三種遍歷方式
package main import "log" type node struct { Item string Left *node Right *node } type bst struct { root *node } /* m k l h i j a b c d e f //先序遍歷(根左右):m k h a b i c d l j e f //中序遍歷(左根右):a h b k c i d m l e j f //后序遍歷(左右根):a b h c d i k e f j l m */ func (tree *bst) buildTree() { m := &node{Item: "m"} tree.root = m k := &node{Item: "k"} l := &node{Item: "l"} m.Left = k m.Right = l h := &node{Item: "h"} i := &node{Item: "i"} k.Left = h k.Right = i a := &node{Item: "a"} b := &node{Item: "b"} h.Left = a h.Right = b c := &node{Item: "c"} d := &node{Item: "d"} i.Left = c i.Right = d j := &node{Item: "j"} l.Right = j e := &node{Item: "e"} f := &node{Item: "f"} j.Left = e j.Right = f } //先序遍歷 func (tree *bst) inOrder() { var inner func(n *node) inner = func(n *node) { if n == nil { return } log.Println(n.Item) inner(n.Left) inner(n.Right) } inner(tree.root) } //中序 func (tree *bst) midOrder() { var inner func(n *node) inner = func(n *node) { if n == nil { return } inner(n.Left) log.Println(n.Item) inner(n.Right) } inner(tree.root) } //后序 func (tree *bst) lastOrder() { var inner func(n *node) inner = func(n *node) { if n == nil { return } inner(n.Left) inner(n.Right) log.Println(n.Item) } inner(tree.root) } func main() { tree := &bst{} tree.buildTree() // tree.inOrder() tree.lastOrder() }
看完上述內容,你們掌握怎么在golang中通過遞歸遍歷生成樹狀結構的方法了嗎?如果還想學到更多技能或想了解更多相關內容,歡迎關注億速云行業資訊頻道,感謝各位的閱讀!
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