您好,登錄后才能下訂單哦!
本篇文章給大家主要講的是關于MySQL中Select Limit使用方法的內容,感興趣的話就一起來看看這篇文章吧,相信看完MySQL中Select Limit使用方法對大家多少有點參考價值吧。
The LIMIT clause can be used to constrain the number of rowsreturned by the SELECT statement.
LIMIT takes one or two numeric arguments,which must both be nonnegative integer constants, with these exceptions:
limit后面可以跟1或2個×××參數,必須是非負整數常量。
Within prepared statements, LIMIT parameters can be specified using? placeholder markers.
在預編譯語句中,limit參數可使用?占位符。
Within stored programs, LIMIT parameters can be specified usinginteger-valued routine
parameters or local variables.
With two arguments, the first argumentspecifies the offset of the first row to return, and the second specifies themaximum number of rows to return. The offset of theinitial row is 0 (not 1):
SELECT * FROM tbl LIMIT5,10; # Retrieve rows 6-15
To retrieve all rows from a certain offsetup to the end of the result set, you can use some large
number for the second parameter. This statement retrieves all rows from the 96th row to thelast:
SELECT * FROM tbl LIMIT95,18446744073709551615;
With one argument, the value specifies thenumber of rows to return from the beginning of the result set:
SELECT * FROM tbl LIMIT5; # Retrieve first 5 rows,返回前5行
In other words, LIMIT row_count isequivalent to LIMIT 0, row_count.
For prepared statements, you can useplaceholders. The following statements will return one row
from the tbl table:
SET @a=1;
PREPARE STMT FROM 'SELECT* FROM tbl LIMIT ?';
EXECUTE STMT USING @a;
The following statements will return thesecond to sixth row from the tbl table:
SET @skip=1; SET@numrows=5;
PREPARE STMT FROM 'SELECT* FROM tbl LIMIT ?, ?';
EXECUTE STMT USING @skip,@numrows;
For compatibility with PostgreSQL, MySQLalso supports the LIMIT row_count OFFSET offset
syntax.
If LIMIT occurs within a subquery and alsois applied in the outer query, the outermost LIMIT takes
precedence. For example, the followingstatement produces two rows, not one:
(SELECT ... LIMIT 1) LIMIT 2;
以上關于MySQL中Select Limit使用方法詳細內容,對大家有幫助嗎?如果想要了解更多相關,可以繼續關注我們的行業資訊板塊。
免責聲明:本站發布的內容(圖片、視頻和文字)以原創、轉載和分享為主,文章觀點不代表本網站立場,如果涉及侵權請聯系站長郵箱:is@yisu.com進行舉報,并提供相關證據,一經查實,將立刻刪除涉嫌侵權內容。