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如何在Python中使用Tkinter實現一個計算器功能?針對這個問題,這篇文章詳細介紹了相對應的分析和解答,希望可以幫助更多想解決這個問題的小伙伴找到更簡單易行的方法。
Python主要應用于:1、Web開發;2、數據科學研究;3、網絡爬蟲;4、嵌入式應用開發;5、游戲開發;6、桌面應用開發。
# -*- coding: utf-8 -*- #author: Cullen #import the module from Tkinter import * import tkFont import os from functools import partial from PIL import Image, ImageTk def get_input(entry, argu): entry.insert(END, argu) def backspace(entry): input_len = len(entry.get()) entry.delete(input_len - 1) def clear(entry): entry.delete(0, END) def calc(entry): input = entry.get() output = str(eval(input.strip())) clear(entry) entry.insert(END, output) def cal(): root = Tk() root.title("Calc") root.resizable(0,0) entry_font = tkFont.Font(size=12) entry = Entry(root, justify="right", font=entry_font) entry.grid(row=0, column=0, columnspan=4, sticky=N+W+S+E, padx=5, pady=5) button_font = tkFont.Font(size=10, weight=tkFont.BOLD) button_bg = '#D5E0EE' button_active_bg = '#E5E35B' myButton = partial(Button, root, bg=button_bg, padx=10, pady=3, activebackground = button_active_bg) button7 = myButton(text='7', command=lambda : get_input(entry, '7')) button7.grid(row=1, column=0, pady=5) button8 = myButton(text='8', command=lambda : get_input(entry, '8')) button8.grid(row=1, column=1, pady=5) button9 = myButton(text='9', command=lambda : get_input(entry, '9')) button9.grid(row=1, column=2, pady=5) button10 = myButton(text='+', command=lambda : get_input(entry, '+')) button10.grid(row=1, column=3, pady=5) button4 = myButton(text='4', command=lambda : get_input(entry, '4')) button4.grid(row=2, column=0, pady=5) button5 = myButton(text='5', command=lambda : get_input(entry, '5')) button5.grid(row=2, column=1, pady=5) button6 = myButton(text='6', command=lambda : get_input(entry, '6')) button6.grid(row=2, column=2, pady=5) button11 = myButton(text='-', command=lambda : get_input(entry, '-')) button11.grid(row=2, column=3, pady=5) button1 = myButton(text='1', command=lambda : get_input(entry, '1')) button1.grid(row=3, column=0, pady=5) button2 = myButton(text='2', command=lambda : get_input(entry, '2')) button2.grid(row=3, column=1, pady=5) button3 = myButton(text='3', command=lambda : get_input(entry, '3')) button3.grid(row=3, column=2, pady=5) button12 = myButton(text='*', command=lambda : get_input(entry, '*')) button12.grid(row=3, column=3, pady=5) button0 = myButton(text='0', command=lambda : get_input(entry, '0')) button0.grid(row=4, column=0, columnspan=2, padx=3, pady=5, sticky=N+S+E+W) button13 = myButton(text='.', command=lambda : get_input(entry, '.')) button13.grid(row=4, column=2, pady=5) button14 = Button(root, text='/', bg=button_bg, padx=10, pady=3, command=lambda : get_input(entry, '/')) button14.grid(row=4, column=3, pady=5) button15 = Button(root, text='<-', bg=button_bg, padx=10, pady=3, command=lambda : backspace(entry), activebackground = button_active_bg) button15.grid(row=5, column=0, pady=5) button16 = Button(root, text='C', bg=button_bg, padx=10, pady=3, command=lambda : clear(entry), activebackground = button_active_bg) button16.grid(row=5, column=1, pady=5) button17 = Button(root, text='=', bg=button_bg, padx=10, pady=3, command=lambda : calc(entry), activebackground = button_active_bg) button17.grid(row=5, column=2, columnspan=2, padx=3, pady=5, sticky=N+S+E+W) root.mainloop() if __name__ == '__main__': cal()
關于如何在Python中使用Tkinter實現一個計算器功能問題的解答就分享到這里了,希望以上內容可以對大家有一定的幫助,如果你還有很多疑惑沒有解開,可以關注億速云行業資訊頻道了解更多相關知識。
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